Simplify - square root of m^4n^7

$- \sqrt{m^{4} n^{7}}$

Step 1

Rewrite $m^{4} n^{7}$ as ${(m^{2} n^{3})}^{2} n$ .

Rewrite $m^{4}$ as ${(m^{2})}^{2}$ .

$- \sqrt{{(m^{2})}^{2} n^{7}}$

Factor out $n^{6}$ .

$- \sqrt{{(m^{2})}^{2} (n^{6} n)}$

Rewrite $n^{6}$ as ${(n^{3})}^{2}$ .

$- \sqrt{{(m^{2})}^{2} ({(n^{3})}^{2} n)}$

Rewrite ${(m^{2})}^{2} {(n^{3})}^{2}$ as ${(m^{2} n^{3})}^{2}$ .

$- \sqrt{{(m^{2} n^{3})}^{2} n}$

Step 2

Pull terms out from under the radical.

$- m^{2} n^{3} \sqrt{n}$