Simplify square root of x^2-16x+64

$\sqrt{x^{2} - 16 x + 64}$

Step 1

Factor using the perfect square rule.

Rewrite $64$ as $8^{2}$ .

$\sqrt{x^{2} - 16 x + 8^{2}}$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$16 x = 2 \cdot x \cdot 8$

Rewrite the polynomial.

$\sqrt{x^{2} - 2 \cdot x \cdot 8 + 8^{2}}$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = x$ and $b = 8$ .

$\sqrt{{(x - 8)}^{2}}$

Step 2

Pull terms out from under the radical, assuming positive real numbers.

$x - 8$