Simplify square root of x^3-x^2+ square root of 9x-9

$\sqrt{x^{3} - x^{2}} + \sqrt{9 x - 9}$

Step 1

Factor $x^{2}$ out of $x^{3} - x^{2}$ .

Factor $x^{2}$ out of $x^{3}$ .

$\sqrt{x^{2} x - x^{2}} + \sqrt{9 x - 9}$

Factor $x^{2}$ out of $- x^{2}$ .

$\sqrt{x^{2} x + x^{2} \cdot - 1} + \sqrt{9 x - 9}$

Factor $x^{2}$ out of $x^{2} x + x^{2} \cdot - 1$ .

$\sqrt{x^{2} (x - 1)} + \sqrt{9 x - 9}$

Step 2

Pull terms out from under the radical.

$x \sqrt{x - 1} + \sqrt{9 x - 9}$

Step 3

Factor $9$ out of $9 x - 9$ .

Factor $9$ out of $9 x$ .

$x \sqrt{x - 1} + \sqrt{9 (x) - 9}$

Factor $9$ out of $- 9$ .

$x \sqrt{x - 1} + \sqrt{9 (x) + 9 (- 1)}$

Factor $9$ out of $9 (x) + 9 (- 1)$ .

$x \sqrt{x - 1} + \sqrt{9 (x - 1)}$

Step 4

Rewrite $9$ as $3^{2}$ .

$x \sqrt{x - 1} + \sqrt{3^{2} (x - 1)}$

Step 5

Pull terms out from under the radical.

$x \sqrt{x - 1} + 3 \sqrt{x - 1}$