Simplify the Radical Expression 3y^(-4/3)*2 cube root of y

$3 y^{- \frac{4}{3}} \cdot 2 \sqrt[3]{y}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$3 \frac{1}{y^{\frac{4}{3}}} \cdot 2 \sqrt[3]{y}$

Combine $3$ and $\frac{1}{y^{\frac{4}{3}}}$ .

$\frac{3}{y^{\frac{4}{3}}} \cdot 2 \sqrt[3]{y}$

Multiply $\frac{3}{y^{\frac{4}{3}}} \cdot 2$ .

Combine $\frac{3}{y^{\frac{4}{3}}}$ and $2$ .

$\frac{3 \cdot 2}{y^{\frac{4}{3}}} \sqrt[3]{y}$

Multiply $3$ by $2$ .

$\frac{6}{y^{\frac{4}{3}}} \sqrt[3]{y}$

Combine $\frac{6}{y^{\frac{4}{3}}}$ and $\sqrt[3]{y}$ .

$\frac{6 \sqrt[3]{y}}{y^{\frac{4}{3}}}$