Simplify the Radical Expression sixth root of cube root of b^11

$\sqrt[6]{\sqrt[3]{b^{11}}}$

Step 1

Rewrite $b^{11}$ as ${(b^{3})}^{3} b^{2}$ .

Factor out $b^{9}$ .

$\sqrt[6]{\sqrt[3]{b^{9} b^{2}}}$

Rewrite $b^{9}$ as ${(b^{3})}^{3}$ .

$\sqrt[6]{\sqrt[3]{{(b^{3})}^{3} b^{2}}}$

Step 2

Pull terms out from under the radical.

$\sqrt[6]{b^{3} \sqrt[3]{b^{2}}}$