Simplify the Radical Expression square root of 3* square root of 12

$\sqrt{3} \cdot \sqrt{12}$

Combine using the product rule for radicals.

$\sqrt{3 \cdot 12}$

Multiply $3$ by $12$ .

$\sqrt{36}$

Rewrite $36$ as $6^{2}$ .

$\sqrt{6^{2}}$

Pull terms out from under the radical.

$| 6 |$

The absolute value is the distance between a number and zero. The distance between $0$ and $6$ is $6$ .

$6$