Simplify the Radical Expression square root of 60x^4y^5

$\sqrt{60 x^{4}} y^{5}$

Step 1

Rewrite $60 x^{4}$ as ${(2 x^{2})}^{2} \cdot 15$ .

Factor $4$ out of $60$ .

$\sqrt{4 (15) x^{4}} y^{5}$

Rewrite $4$ as $2^{2}$ .

$\sqrt{2^{2} \cdot 15 x^{4}} y^{5}$

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$\sqrt{2^{2} \cdot 15 {(x^{2})}^{2}} y^{5}$

Move $15$ .

$\sqrt{2^{2} {(x^{2})}^{2} \cdot 15} y^{5}$

Rewrite $2^{2} {(x^{2})}^{2}$ as ${(2 x^{2})}^{2}$ .

$\sqrt{{(2 x^{2})}^{2} \cdot 15} y^{5}$

Step 2

Pull terms out from under the radical.

$| 2 x^{2} | \sqrt{15} y^{5}$

Step 3

Remove non-negative terms from the absolute value.

$2 x^{2} \sqrt{15} y^{5}$