Simplify (v^-1)^(1/9)

${(v^{- 1})}^{\frac{1}{9}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$v^{- \frac{1}{9}}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{v^{\frac{1}{9}}}$