Simplify (x^0y^-2)^(6/3)

${(x^{0} y^{- 2})}^{\frac{6}{3}}$

Step 1

Anything raised to $0$ is $1$ .

${(1 y^{- 2})}^{\frac{6}{3}}$

Step 2

Multiply $y^{- 2}$ by $1$ .

${(y^{- 2})}^{\frac{6}{3}}$

Step 3

Multiply the exponents in ${(y^{- 2})}^{\frac{6}{3}}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y^{- 2 (\frac{6}{3})}$

Divide $6$ by $3$ .

$y^{- 2 \cdot 2}$

Multiply $- 2$ by $2$ .

$y^{- 4}$

Step 4

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{y^{4}}$