Simplify (x^2+10x-11)/(x^2+7x-8)

$\frac{x^{2} + 10 x - 11}{x^{2} + 7 x - 8}$

Step 1

Factor $x^{2} + 10 x - 11$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 11$ and whose sum is $10$ .

$- 1, 11$

Write the factored form using these integers.

$\frac{(x - 1) (x + 11)}{x^{2} + 7 x - 8}$

Step 2

Factor $x^{2} + 7 x - 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 8$ and whose sum is $7$ .

$- 1, 8$

Write the factored form using these integers.

$\frac{(x - 1) (x + 11)}{(x - 1) (x + 8)}$

Step 3

Cancel the common factor of $x - 1$ .

Cancel the common factor.

$\frac{(x - 1) (x + 11)}{(x - 1) (x + 8)}$

Rewrite the expression.

$\frac{x + 11}{x + 8}$

Simplify (x^2+10x-11)/(x^2+7x-8)

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