Simplify (x+2)/(2x+10)-(-2x+8)/(x^2+x-20)

$\frac{x + 2}{2 x + 10} - \frac{- 2 x + 8}{x^{2} + x - 20}$

Step 1

Simplify each term.

Factor $2$ out of $2 x + 10$ .

Factor $2$ out of $2 x$ .

$\frac{x + 2}{2 (x) + 10} - \frac{- 2 x + 8}{x^{2} + x - 20}$

Factor $2$ out of $10$ .

$\frac{x + 2}{2 x + 2 \cdot 5} - \frac{- 2 x + 8}{x^{2} + x - 20}$

Factor $2$ out of $2 x + 2 \cdot 5$ .

$\frac{x + 2}{2 (x + 5)} - \frac{- 2 x + 8}{x^{2} + x - 20}$

Factor $2$ out of $- 2 x + 8$ .

Factor $2$ out of $- 2 x$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- x) + 8}{x^{2} + x - 20}$

Factor $2$ out of $8$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- x) + 2 (4)}{x^{2} + x - 20}$

Factor $2$ out of $2 (- x) + 2 (4)$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- x + 4)}{x^{2} + x - 20}$

Factor $x^{2} + x - 20$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 20$ and whose sum is $1$ .

$- 4, 5$

Write the factored form using these integers.

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- x + 4)}{(x - 4) (x + 5)}$

Cancel the common factor of $- x + 4$ and $x - 4$ .

Factor $- 1$ out of $- x$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- (x) + 4)}{(x - 4) (x + 5)}$

Rewrite $4$ as $- 1 (- 4)$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- (x) - 1 (- 4))}{(x - 4) (x + 5)}$

Factor $- 1$ out of $- (x) - 1 (- 4)$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- (x - 4))}{(x - 4) (x + 5)}$

Rewrite $- (x - 4)$ as $- 1 (x - 4)$ .

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- 1 (x - 4))}{(x - 4) (x + 5)}$

Cancel the common factor.

$\frac{x + 2}{2 (x + 5)} - \frac{2 (- 1 (x - 4))}{(x - 4) (x + 5)}$

Rewrite the expression.

$\frac{x + 2}{2 (x + 5)} - \frac{2 \cdot (- 1)}{x + 5}$

Multiply $2$ by $- 1$ .

$\frac{x + 2}{2 (x + 5)} - \frac{- 2}{x + 5}$

Move the negative in front of the fraction.

$\frac{x + 2}{2 (x + 5)} - - \frac{2}{x + 5}$

Multiply $- - \frac{2}{x + 5}$ .

Multiply $- 1$ by $- 1$ .

$\frac{x + 2}{2 (x + 5)} + 1 \frac{2}{x + 5}$

Multiply $\frac{2}{x + 5}$ by $1$ .

$\frac{x + 2}{2 (x + 5)} + \frac{2}{x + 5}$

Step 2

To write $\frac{2}{x + 5}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{x + 2}{2 (x + 5)} + \frac{2}{x + 5} \cdot \frac{2}{2}$

Step 3

Write each expression with a common denominator of $2 (x + 5)$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{2}{x + 5}$ by $\frac{2}{2}$ .

$\frac{x + 2}{2 (x + 5)} + \frac{2 \cdot 2}{(x + 5) \cdot 2}$

Reorder the factors of $(x + 5) \cdot 2$ .

$\frac{x + 2}{2 (x + 5)} + \frac{2 \cdot 2}{2 (x + 5)}$

Step 4

Combine the numerators over the common denominator.

$\frac{x + 2 + 2 \cdot 2}{2 (x + 5)}$

Step 5

Simplify the numerator.

Multiply $2$ by $2$ .

$\frac{x + 2 + 4}{2 (x + 5)}$

Add $2$ and $4$ .

$\frac{x + 6}{2 (x + 5)}$

Simplify (x+2)/(2x+10)-(-2x+8)/(x^2+x-20)

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