Simplify (x^2-2x-37)÷(x^2-3x-40)

$(x^{2} - 2 x - 37) \div (x^{2} - 3 x - 40)$

Step 1

Rewrite the division as a fraction.

$\frac{x^{2} - 2 x - 37}{x^{2} - 3 x - 40}$

Step 2

Factor $x^{2} - 3 x - 40$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 40$ and whose sum is $- 3$ .

$- 8, 5$

Write the factored form using these integers.

$\frac{x^{2} - 2 x - 37}{(x - 8) (x + 5)}$

Simplify (x^2-2x-37)÷(x^2-3x-40)

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