Simplify (x^2-3x-40)/(x+5)

$\frac{x^{2} - 3 x - 40}{x + 5}$

Step 1

Factor $x^{2} - 3 x - 40$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 40$ and whose sum is $- 3$ .

$- 8, 5$

Write the factored form using these integers.

$\frac{(x - 8) (x + 5)}{x + 5}$

Step 2

Cancel the common factor of $x + 5$ .

Cancel the common factor.

$\frac{(x - 8) (x + 5)}{x + 5}$

Divide $x - 8$ by $1$ .

$x - 8$

Simplify (x^2-3x-40)/(x+5)

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