Simplify (x^2+3x-9)(4-x)^-1

$(x^{2} + 3 x - 9) {(4 - x)}^{- 1}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(x^{2} + 3 x - 9) \frac{1}{4 - x}$

Step 2

Multiply $x^{2} + 3 x - 9$ by $\frac{1}{4 - x}$ .

$\frac{x^{2} + 3 x - 9}{4 - x}$