Simplify (x^2-4)/(1-6x)

$\frac{x^{2} - 4}{1 - 6 x}$

Rewrite $4$ as $2^{2}$ .

$\frac{x^{2} - 2^{2}}{1 - 6 x}$

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{(x + 2) (x - 2)}{1 - 6 x}$