Simplify ((x^2-5x+4)/(x^2))÷((x-1)/x)

$\frac{x^{2} - 5 x + 4}{x^{2}} \div \frac{x - 1}{x}$

To divide by a fraction, multiply by its reciprocal.

$\frac{x^{2} - 5 x + 4}{x^{2}} \cdot \frac{x}{x - 1}$

Simplify terms.

Cancel the common factor of $x$ .

Factor $x$ out of $x^{2}$ .

$\frac{x^{2} - 5 x + 4}{x \cdot x} \cdot \frac{x}{x - 1}$

Cancel the common factor.

$\frac{x^{2} - 5 x + 4}{x \cdot x} \cdot \frac{x}{x - 1}$

Rewrite the expression.

$\frac{x^{2} - 5 x + 4}{x} \cdot \frac{1}{x - 1}$

Multiply $\frac{x^{2} - 5 x + 4}{x}$ by $\frac{1}{x - 1}$ .

$\frac{x^{2} - 5 x + 4}{x (x - 1)}$

Factor $x^{2} - 5 x + 4$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $4$ and whose sum is $- 5$ .

$- 4, - 1$

Write the factored form using these integers.

$\frac{(x - 4) (x - 1)}{x (x - 1)}$

Cancel the common factor of $x - 1$ .

Cancel the common factor.

$\frac{(x - 4) (x - 1)}{x (x - 1)}$

Rewrite the expression.

$\frac{x - 4}{x}$

Simplify ((x^2-5x+4)/(x^2))÷((x-1)/x)

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