Simplify (x^2(x^2-5x-14))/(4x(x^2+6x+8))

$\frac{x^{2} (x^{2} - 5 x - 14)}{4 x (x^{2} + 6 x + 8)}$

Cancel the common factor of $x^{2}$ and $x$ .

Factor $x$ out of $x^{2} (x^{2} - 5 x - 14)$ .

$\frac{x (x (x^{2} - 5 x - 14))}{4 x (x^{2} + 6 x + 8)}$

Cancel the common factors.

Factor $x$ out of $4 x (x^{2} + 6 x + 8)$ .

$\frac{x (x (x^{2} - 5 x - 14))}{x (4 (x^{2} + 6 x + 8))}$

Cancel the common factor.

$\frac{x (x (x^{2} - 5 x - 14))}{x (4 (x^{2} + 6 x + 8))}$

Rewrite the expression.

$\frac{x (x^{2} - 5 x - 14)}{4 (x^{2} + 6 x + 8)}$

Factor $x^{2} - 5 x - 14$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 14$ and whose sum is $- 5$ .

$- 7, 2$

Write the factored form using these integers.

$\frac{x ((x - 7) (x + 2))}{4 (x^{2} + 6 x + 8)}$

$\frac{x (x - 7) (x + 2)}{4 (x^{2} + 6 x + 8)}$

Factor $x^{2} + 6 x + 8$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $8$ and whose sum is $6$ .

$2, 4$

Write the factored form using these integers.

$\frac{x (x - 7) (x + 2)}{4 ((x + 2) (x + 4))}$

$\frac{x (x - 7) (x + 2)}{4 (x + 2) (x + 4)}$

Cancel the common factor of $x + 2$ .

Cancel the common factor.

$\frac{x (x - 7) (x + 2)}{4 (x + 2) (x + 4)}$

Rewrite the expression.

$\frac{x (x - 7)}{4 (x + 4)}$

Simplify (x^2(x^2-5x-14))/(4x(x^2+6x+8))

Related Questions

Support LCMGCF.com by disabling your adblocker.