Simplify (x^2+x-6)/(x^2-2x-15)

$\frac{x^{2} + x - 6}{x^{2} - 2 x - 15}$

Step 1

Factor $x^{2} + x - 6$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 6$ and whose sum is $1$ .

$- 2, 3$

Write the factored form using these integers.

$\frac{(x - 2) (x + 3)}{x^{2} - 2 x - 15}$

Step 2

Factor $x^{2} - 2 x - 15$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 15$ and whose sum is $- 2$ .

$- 5, 3$

Write the factored form using these integers.

$\frac{(x - 2) (x + 3)}{(x - 5) (x + 3)}$

Step 3

Cancel the common factor of $x + 3$ .

Cancel the common factor.

$\frac{(x - 2) (x + 3)}{(x - 5) (x + 3)}$

Rewrite the expression.

$\frac{x - 2}{x - 5}$

Simplify (x^2+x-6)/(x^2-2x-15)

Related Questions

Support LCMGCF.com by disabling your adblocker.