Simplify (x^2+y^2)^3

${(x^{2} + y^{2})}^{3}$

Step 1

Use the Binomial Theorem.

${(x^{2})}^{3} + 3 {(x^{2})}^{2} y^{2} + 3 x^{2} {(y^{2})}^{2} + {(y^{2})}^{3}$

Step 2

Simplify each term.

Multiply the exponents in ${(x^{2})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{2 \cdot 3} + 3 {(x^{2})}^{2} y^{2} + 3 x^{2} {(y^{2})}^{2} + {(y^{2})}^{3}$

Multiply $2$ by $3$ .

$x^{6} + 3 {(x^{2})}^{2} y^{2} + 3 x^{2} {(y^{2})}^{2} + {(y^{2})}^{3}$

Multiply the exponents in ${(x^{2})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{6} + 3 x^{2 \cdot 2} y^{2} + 3 x^{2} {(y^{2})}^{2} + {(y^{2})}^{3}$

Multiply $2$ by $2$ .

$x^{6} + 3 x^{4} y^{2} + 3 x^{2} {(y^{2})}^{2} + {(y^{2})}^{3}$

Multiply the exponents in ${(y^{2})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{6} + 3 x^{4} y^{2} + 3 x^{2} y^{2 \cdot 2} + {(y^{2})}^{3}$

Multiply $2$ by $2$ .

$x^{6} + 3 x^{4} y^{2} + 3 x^{2} y^{4} + {(y^{2})}^{3}$

Multiply the exponents in ${(y^{2})}^{3}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x^{6} + 3 x^{4} y^{2} + 3 x^{2} y^{4} + y^{2 \cdot 3}$

Multiply $2$ by $3$ .

$x^{6} + 3 x^{4} y^{2} + 3 x^{2} y^{4} + y^{6}$