Simplify (x^3+10x^2)/(x^2+2x-80)

$\frac{x^{3} + 10 x^{2}}{x^{2} + 2 x - 80}$

Step 1

Factor $x^{2}$ out of $x^{3} + 10 x^{2}$ .

Factor $x^{2}$ out of $x^{3}$ .

$\frac{x^{2} x + 10 x^{2}}{x^{2} + 2 x - 80}$

Factor $x^{2}$ out of $10 x^{2}$ .

$\frac{x^{2} x + x^{2} \cdot 10}{x^{2} + 2 x - 80}$

Factor $x^{2}$ out of $x^{2} x + x^{2} \cdot 10$ .

$\frac{x^{2} (x + 10)}{x^{2} + 2 x - 80}$

Step 2

Factor $x^{2} + 2 x - 80$ using the AC method.

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 80$ and whose sum is $2$ .

$- 8, 10$

Write the factored form using these integers.

$\frac{x^{2} (x + 10)}{(x - 8) (x + 10)}$

Step 3

Cancel the common factor of $x + 10$ .

Cancel the common factor.

$\frac{x^{2} (x + 10)}{(x - 8) (x + 10)}$

Rewrite the expression.

$\frac{x^{2}}{x - 8}$

Simplify (x^3+10x^2)/(x^2+2x-80)

Related Questions

Support LCMGCF.com by disabling your adblocker.