Simplify ((x^3-64x)/(x-10)*(x^2-5x+6)/(x^2-4))÷((x^2-11x+24)/(x^2-8x-20))

Factor ${\displaystyle x}$ out of ${\displaystyle x^3-64x}$.

Rewrite ${\displaystyle 64}$ as ${\displaystyle 8^2}$.

Since both terms are perfect squares, factor using the difference of squares formula, ${\displaystyle a^2-b^2=(a+b)(a-b)}$ where ${\displaystyle a=x}$ and ${\displaystyle b=8}$.

Consider the form ${\displaystyle x^2+bx+c}$. Find a pair of integers whose product is ${\displaystyle c}$ and whose sum is ${\displaystyle b}$. In this case, whose product is ${\displaystyle 6}$ and whose sum is ${\displaystyle -5}$.

Write the factored form using these integers.

Rewrite ${\displaystyle 4}$ as ${\displaystyle 2^2}$.

Since both terms are perfect squares, factor using the difference of squares formula, ${\displaystyle a^2-b^2=(a+b)(a-b)}$ where ${\displaystyle a=x}$ and ${\displaystyle b=2}$.

Cancel the common factor of ${\displaystyle x-2}$.

Multiply ${\displaystyle \frac{x(x+8)(x-8)}{x-10}}$ by ${\displaystyle \frac{x-3}{x+2}}$.

Consider the form ${\displaystyle x^2+bx+c}$. Find a pair of integers whose product is ${\displaystyle c}$ and whose sum is ${\displaystyle b}$. In this case, whose product is ${\displaystyle -20}$ and whose sum is ${\displaystyle -8}$.

Write the factored form using these integers.

Consider the form ${\displaystyle x^2+bx+c}$. Find a pair of integers whose product is ${\displaystyle c}$ and whose sum is ${\displaystyle b}$. In this case, whose product is ${\displaystyle 24}$ and whose sum is ${\displaystyle -11}$.

Write the factored form using these integers.

Cancel the common factor of ${\displaystyle (x-8)(x-3)}$.

Cancel the common factor of ${\displaystyle (x-10)(x+2)}$.

Apply the distributive property.

Simplify the expression.