Simplify (x^4-3x^3+5x-6)(x+2)^-1

$(x^{4} - 3 x^{3} + 5 x - 6) {(x + 2)}^{- 1}$

Step 1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(x^{4} - 3 x^{3} + 5 x - 6) \frac{1}{x + 2}$

Step 2

Multiply $x^{4} - 3 x^{3} + 5 x - 6$ by $\frac{1}{x + 2}$ .

$\frac{x^{4} - 3 x^{3} + 5 x - 6}{x + 2}$