Simplify x/-9>=3

$\frac{x}{- 9} \geq 3$

Multiply both sides by $- 9$ .

$\frac{x}{- 9} \cdot - 9 \leq 3 \cdot - 9$

Simplify.

Simplify the left side.

Simplify $\frac{x}{- 9} \cdot - 9$ .

Cancel the common factor of $9$ .

Factor $9$ out of $- 9$ .

$\frac{x}{9 (- 1)} \cdot - 9 \leq 3 \cdot - 9$

Factor $9$ out of $- 9$ .

$\frac{x}{9 \cdot - 1} \cdot (9 \cdot - 1) \leq 3 \cdot - 9$

Cancel the common factor.

$\frac{x}{9 \cdot - 1} \cdot (9 \cdot - 1) \leq 3 \cdot - 9$

Rewrite the expression.

$\frac{x}{- 1} \cdot - 1 \leq 3 \cdot - 9$

Combine $\frac{x}{- 1}$ and $- 1$ .

$\frac{x \cdot - 1}{- 1} \leq 3 \cdot - 9$

Simplify the expression.

Move the negative one from the denominator of $\frac{x \cdot - 1}{- 1}$ .

$- 1 \cdot (x \cdot - 1) \leq 3 \cdot - 9$

Rewrite $- 1 \cdot (x \cdot - 1)$ as $- (x \cdot - 1)$ .

$- (x \cdot - 1) \leq 3 \cdot - 9$

Move $- 1$ to the left of $x$ .

$- (- 1 \cdot x) \leq 3 \cdot - 9$

Rewrite $- 1 x$ as $- x$ .

$- - x \leq 3 \cdot - 9$

Multiply $- - x$ .

Multiply $- 1$ by $- 1$ .

$1 x \leq 3 \cdot - 9$

Multiply $x$ by $1$ .

$x \leq 3 \cdot - 9$

Simplify the right side.

Multiply $3$ by $- 9$ .

$x \leq - 27$

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 27$

Interval Notation:

$(- \infty, - 27]$