Simplify (z^4-3z^3+2z^2-4z+4)(z-1)^-1

$(z^{4} - 3 z^{3} + 2 z^{2} - 4 z + 4) {(z - 1)}^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$(z^{4} - 3 z^{3} + 2 z^{2} - 4 z + 4) \frac{1}{z - 1}$