Solve by Addition/Elimination -12x-5y=40 12x-11y=88

$- 12 x - 5 y = 40$ $12 x - 11 y = 88$

Step 1

Add the two equations together to eliminate $x$ from the system.

	$-$	$1$	$2$	$x$		$-$	$5$	$y$	$=$	$4$	$0$
$+$		$1$	$2$	$x$	$-$	$1$	$1$	$y$	$=$	$8$	$8$
					$-$	$1$	$6$	$y$	$=$	$1$	$2$	$8$

Step 2

Divide each term in $- 16 y = 128$ by $- 16$ and simplify.

Divide each term in $- 16 y = 128$ by $- 16$ .

$\frac{- 16 y}{- 16} = \frac{128}{- 16}$

Simplify the left side.

Cancel the common factor of $- 16$ .

Cancel the common factor.

$\frac{- 16 y}{- 16} = \frac{128}{- 16}$

Divide $y$ by $1$ .

$y = \frac{128}{- 16}$

Simplify the right side.

Divide $128$ by $- 16$ .

$y = - 8$

Step 3

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$- 12 x - 5 \cdot - 8 = 40$

Multiply $- 5$ by $- 8$ .

$- 12 x + 40 = 40$

Move all terms not containing $x$ to the right side of the equation.

Subtract $40$ from both sides of the equation.

$- 12 x = 40 - 40$

Subtract $40$ from $40$ .

$- 12 x = 0$

Divide each term in $- 12 x = 0$ by $- 12$ and simplify.

Divide each term in $- 12 x = 0$ by $- 12$ .

$\frac{- 12 x}{- 12} = \frac{0}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 x}{- 12} = \frac{0}{- 12}$

Divide $x$ by $1$ .

$x = \frac{0}{- 12}$

Simplify the right side.

Divide $0$ by $- 12$ .

$x = 0$

Step 4

The solution to the independent system of equations can be represented as a point.

$(0, - 8)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(0, - 8)$

Equation Form:

$x = 0, y = - 8$

Step 6

Solve by Addition/Elimination -12x-5y=40 12x-11y=88

Related Questions

Support LCMGCF.com by disabling your adblocker.