Solve by Addition/Elimination 2x+4y=11 3x+6y=17

$2 x + 4 y = 11$ $3 x + 6 y = 17$

Step 1

Multiply each equation by the value that makes the coefficients of $x$ opposite.

$(- 3) \cdot (2 x + 4 y) = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

Step 2

Simplify.

Simplify the left side.

Simplify $(- 3) \cdot (2 x + 4 y)$ .

Apply the distributive property.

$- 3 (2 x) - 3 (4 y) = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

Multiply.

Multiply $2$ by $- 3$ .

$- 6 x - 3 (4 y) = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

Multiply $4$ by $- 3$ .

$- 6 x - 12 y = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

$- 6 x - 12 y = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

$- 6 x - 12 y = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

$- 6 x - 12 y = (- 3) (11)$

$(2) \cdot (3 x + 6 y) = (2) (17)$

Simplify the right side.

Multiply $- 3$ by $11$ .

$- 6 x - 12 y = - 33$

$(2) \cdot (3 x + 6 y) = (2) (17)$

$- 6 x - 12 y = - 33$

$(2) \cdot (3 x + 6 y) = (2) (17)$

Simplify the left side.

Simplify $(2) \cdot (3 x + 6 y)$ .

Apply the distributive property.

$- 6 x - 12 y = - 33$

$2 (3 x) + 2 (6 y) = (2) (17)$

Multiply.

Multiply $3$ by $2$ .

$- 6 x - 12 y = - 33$

$6 x + 2 (6 y) = (2) (17)$

Multiply $6$ by $2$ .

$- 6 x - 12 y = - 33$

$6 x + 12 y = (2) (17)$

$- 6 x - 12 y = - 33$

$6 x + 12 y = (2) (17)$

$- 6 x - 12 y = - 33$

$6 x + 12 y = (2) (17)$

$- 6 x - 12 y = - 33$

$6 x + 12 y = (2) (17)$

Simplify the right side.

Multiply $2$ by $17$ .

$- 6 x - 12 y = - 33$

$6 x + 12 y = 34$

$- 6 x - 12 y = - 33$

$6 x + 12 y = 34$

$- 6 x - 12 y = - 33$

$6 x + 12 y = 34$

Step 3

Add the two equations together to eliminate $x$ from the system.

	$-$	$6$	$x$	$-$	$1$	$2$	$y$	$=$	$-$	$3$	$3$
$+$		$6$	$x$	$+$	$1$	$2$	$y$	$=$		$3$	$4$
							$0$	$=$			$1$

Step 4

Since $0 \neq 1$ , there are no solutions.

No solution

Step 5

Solve by Addition/Elimination 2x+4y=11 3x+6y=17

Related Questions

Support LCMGCF.com by disabling your adblocker.