Solve by Addition/Elimination 2x-5y=6 -2x+10y=-16

$2 x - 5 y = 6$ $- 2 x + 10 y = - 16$

Add the two equations together to eliminate $x$ from the system.

Divide each term in $5 y = - 10$ by $5$ and simplify.

Divide each term in $5 y = - 10$ by $5$ .

$\frac{5 y}{5} = \frac{- 10}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 y}{5} = \frac{- 10}{5}$

Divide $y$ by $1$ .

$y = \frac{- 10}{5}$

Simplify the right side.

Divide $- 10$ by $5$ .

$y = - 2$

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$2 x - 5 \cdot - 2 = 6$

Multiply $- 5$ by $- 2$ .

$2 x + 10 = 6$

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$2 x = 6 - 10$

Subtract $10$ from $6$ .

$2 x = - 4$

Divide each term in $2 x = - 4$ by $2$ and simplify.

Divide each term in $2 x = - 4$ by $2$ .

$\frac{2 x}{2} = \frac{- 4}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 4}{2}$

Divide $x$ by $1$ .

$x = \frac{- 4}{2}$

Simplify the right side.

Divide $- 4$ by $2$ .

$x = - 2$

The solution to the independent system of equations can be represented as a point.

$(- 2, - 2)$

The result can be shown in multiple forms.

Point Form:

$(- 2, - 2)$

Equation Form:

$x = - 2, y = - 2$