Solve by Addition/Elimination 2x+y=-1 , 4x-y=-11

$2 x + y = - 1$ , $4 x - y = - 11$

Step 1

Add the two equations together to eliminate $y$ from the system.

Step 2

Divide each term in $6 x = - 12$ by $6$ and simplify.

Divide each term in $6 x = - 12$ by $6$ .

$\frac{6 x}{6} = \frac{- 12}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{- 12}{6}$

Divide $x$ by $1$ .

$x = \frac{- 12}{6}$

Simplify the right side.

Divide $- 12$ by $6$ .

$x = - 2$

Step 3

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$2 (- 2) + y = - 1$

Multiply $2$ by $- 2$ .

$- 4 + y = - 1$

Move all terms not containing $y$ to the right side of the equation.

Add $4$ to both sides of the equation.

$y = - 1 + 4$

Add $- 1$ and $4$ .

$y = 3$

Step 4

The solution to the independent system of equations can be represented as a point.

$(- 2, 3)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 2, 3)$

Equation Form:

$x = - 2, y = 3$

Step 6