Solve by Addition/Elimination 3x+6y=27 x+2y=11

$3 x + 6 y = 27$ $x + 2 y = 11$

Multiply each equation by the value that makes the coefficients of $x$ opposite.

$3 x + 6 y = 27$

$(- 3) \cdot (x + 2 y) = (- 3) (11)$

Simplify.

Simplify the left side.

Simplify $(- 3) \cdot (x + 2 y)$ .

Apply the distributive property.

$3 x + 6 y = 27$

$- 3 x - 3 (2 y) = (- 3) (11)$

Multiply $2$ by $- 3$ .

$3 x + 6 y = 27$

$- 3 x - 6 y = (- 3) (11)$

$3 x + 6 y = 27$

$- 3 x - 6 y = (- 3) (11)$

$3 x + 6 y = 27$

$- 3 x - 6 y = (- 3) (11)$

Simplify the right side.

Multiply $- 3$ by $11$ .

$3 x + 6 y = 27$

$- 3 x - 6 y = - 33$

$3 x + 6 y = 27$

$- 3 x - 6 y = - 33$

$3 x + 6 y = 27$

$- 3 x - 6 y = - 33$

Add the two equations together to eliminate $x$ from the system.

Since $0 \neq - 6$ , there are no solutions.

No solution