Solve by Addition/Elimination 4x+8y=20 -4x+2y=-30

$4 x + 8 y = 20$ $- 4 x + 2 y = - 30$

Step 1

Add the two equations together to eliminate $x$ from the system.

		$4$	$x$	$+$	$8$	$y$	$=$		$2$	$0$
$+$	$-$	$4$	$x$	$+$	$2$	$y$	$=$	$-$	$3$	$0$
				$1$	$0$	$y$	$=$	$-$	$1$	$0$

Step 2

Divide each term in $10 y = - 10$ by $10$ and simplify.

Divide each term in $10 y = - 10$ by $10$ .

$\frac{10 y}{10} = \frac{- 10}{10}$

Simplify the left side.

Cancel the common factor of $10$ .

Cancel the common factor.

$\frac{10 y}{10} = \frac{- 10}{10}$

Divide $y$ by $1$ .

$y = \frac{- 10}{10}$

Simplify the right side.

Divide $- 10$ by $10$ .

$y = - 1$

Step 3

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$4 x + 8 (- 1) = 20$

Multiply $8$ by $- 1$ .

$4 x - 8 = 20$

Move all terms not containing $x$ to the right side of the equation.

Add $8$ to both sides of the equation.

$4 x = 20 + 8$

Add $20$ and $8$ .

$4 x = 28$

Divide each term in $4 x = 28$ by $4$ and simplify.

Divide each term in $4 x = 28$ by $4$ .

$\frac{4 x}{4} = \frac{28}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{28}{4}$

Divide $x$ by $1$ .

$x = \frac{28}{4}$

Simplify the right side.

Divide $28$ by $4$ .

$x = 7$

Step 4

The solution to the independent system of equations can be represented as a point.

$(7, - 1)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(7, - 1)$

Equation Form:

$x = 7, y = - 1$

Step 6

Solve by Addition/Elimination 4x+8y=20 -4x+2y=-30

Related Questions

Support LCMGCF.com by disabling your adblocker.