Solve by Addition/Elimination 4y=2x-8 5x-4y=20

$4 y = 2 x - 8$ $5 x - 4 y = 20$

Move all terms containing variables to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$4 y - 2 x = - 8$

$5 x - 4 y = 20$

Reorder $4 y$ and $- 2 x$ .

$- 2 x + 4 y = - 8$

$5 x - 4 y = 20$

$- 2 x + 4 y = - 8$

$5 x - 4 y = 20$

Add the two equations together to eliminate $y$ from the system.

	$-$	$2$	$x$	$+$	$4$	$y$	$=$	$-$	$8$
$+$		$5$	$x$	$-$	$4$	$y$	$=$	$2$	$0$
		$3$	$x$				$=$	$1$	$2$

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$- 2 \cdot 4 + 4 y = - 8$

Multiply $- 2$ by $4$ .

$- 8 + 4 y = - 8$

Move all terms not containing $y$ to the right side of the equation.

Add $8$ to both sides of the equation.

$4 y = - 8 + 8$

Add $- 8$ and $8$ .

$4 y = 0$

Divide each term in $4 y = 0$ by $4$ and simplify.

Divide each term in $4 y = 0$ by $4$ .

$\frac{4 y}{4} = \frac{0}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{0}{4}$

Divide $y$ by $1$ .

$y = \frac{0}{4}$

Simplify the right side.

Divide $0$ by $4$ .

$y = 0$

The solution to the independent system of equations can be represented as a point.

$(4, 0)$

The result can be shown in multiple forms.

Point Form:

$(4, 0)$

Equation Form:

$x = 4, y = 0$

Solve by Addition/Elimination 4y=2x-8 5x-4y=20

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