Solve by Addition/Elimination 4y=-3-x 7x-4y=43

$4 y = - 3 - x$ $7 x - 4 y = 43$

Simplify the right side.

Reorder $- 3$ and $- x$ .

$4 y = - x - 3$

$7 x - 4 y = 43$

$4 y = - x - 3$

$7 x - 4 y = 43$

Move all terms containing variables to the left side of the equation.

Add $x$ to both sides of the equation.

$4 y + x = - 3$

$7 x - 4 y = 43$

Reorder $4 y$ and $x$ .

$x + 4 y = - 3$

$7 x - 4 y = 43$

$x + 4 y = - 3$

$7 x - 4 y = 43$

Add the two equations together to eliminate $y$ from the system.

		$x$	$+$	$4$	$y$	$=$	$-$	$3$
$+$	$7$	$x$	$-$	$4$	$y$	$=$	$4$	$3$
	$8$	$x$				$=$	$4$	$0$

Divide each term in $8 x = 40$ by $8$ and simplify.

Divide each term in $8 x = 40$ by $8$ .

$\frac{8 x}{8} = \frac{40}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 x}{8} = \frac{40}{8}$

Divide $x$ by $1$ .

$x = \frac{40}{8}$

Simplify the right side.

Divide $40$ by $8$ .

$x = 5$

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$(5) + 4 y = - 3$

Remove parentheses.

$5 + 4 y = - 3$

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$4 y = - 3 - 5$

Subtract $5$ from $- 3$ .

$4 y = - 8$

Divide each term in $4 y = - 8$ by $4$ and simplify.

Divide each term in $4 y = - 8$ by $4$ .

$\frac{4 y}{4} = \frac{- 8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{- 8}{4}$

Divide $y$ by $1$ .

$y = \frac{- 8}{4}$

Simplify the right side.

Divide $- 8$ by $4$ .

$y = - 2$

The solution to the independent system of equations can be represented as a point.

$(5, - 2)$

The result can be shown in multiple forms.

Point Form:

$(5, - 2)$

Equation Form:

$x = 5, y = - 2$

Solve by Addition/Elimination 4y=-3-x 7x-4y=43

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