Solve by Addition/Elimination 6x-6=-8y , 5x+4y=-11

$6 x - 6 = - 8 y$ , $5 x + 4 y = - 11$

Move all terms containing variables to the left side of the equation.

Add $8 y$ to both sides of the equation.

$6 x - 6 + 8 y = 0$

$5 x + 4 y = - 11$

Move $- 6$ .

$6 x + 8 y - 6 = 0$

$5 x + 4 y = - 11$

$6 x + 8 y - 6 = 0$

$5 x + 4 y = - 11$

Add $6$ to both sides of the equation.

$6 x + 8 y = 6$

$5 x + 4 y = - 11$

Multiply each equation by the value that makes the coefficients of $y$ opposite.

$6 x + 8 y = 6$

$(- 2) \cdot (5 x + 4 y) = (- 2) (- 11)$

Simplify.

Simplify the left side.

Simplify $(- 2) \cdot (5 x + 4 y)$ .

Apply the distributive property.

$6 x + 8 y = 6$

$- 2 (5 x) - 2 (4 y) = (- 2) (- 11)$

Multiply.

Multiply $5$ by $- 2$ .

$6 x + 8 y = 6$

$- 10 x - 2 (4 y) = (- 2) (- 11)$

Multiply $4$ by $- 2$ .

$6 x + 8 y = 6$

$- 10 x - 8 y = (- 2) (- 11)$

$6 x + 8 y = 6$

$- 10 x - 8 y = (- 2) (- 11)$

$6 x + 8 y = 6$

$- 10 x - 8 y = (- 2) (- 11)$

$6 x + 8 y = 6$

$- 10 x - 8 y = (- 2) (- 11)$

Simplify the right side.

Multiply $- 2$ by $- 11$ .

$6 x + 8 y = 6$

$- 10 x - 8 y = 22$

$6 x + 8 y = 6$

$- 10 x - 8 y = 22$

$6 x + 8 y = 6$

$- 10 x - 8 y = 22$

Add the two equations together to eliminate $y$ from the system.

			$6$	$x$	$+$	$8$	$y$	$=$		$6$
$+$	$-$	$1$	$0$	$x$	$-$	$8$	$y$	$=$	$2$	$2$
		$-$	$4$	$x$				$=$	$2$	$8$

Divide each term in $- 4 x = 28$ by $- 4$ and simplify.

Divide each term in $- 4 x = 28$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{28}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{28}{- 4}$

Divide $x$ by $1$ .

$x = \frac{28}{- 4}$

Simplify the right side.

Divide $28$ by $- 4$ .

$x = - 7$

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$6 (- 7) + 8 y = 6$

Multiply $6$ by $- 7$ .

$- 42 + 8 y = 6$

Move all terms not containing $y$ to the right side of the equation.

Add $42$ to both sides of the equation.

$8 y = 6 + 42$

Add $6$ and $42$ .

$8 y = 48$

Divide each term in $8 y = 48$ by $8$ and simplify.

Divide each term in $8 y = 48$ by $8$ .

$\frac{8 y}{8} = \frac{48}{8}$

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{8 y}{8} = \frac{48}{8}$

Divide $y$ by $1$ .

$y = \frac{48}{8}$

Simplify the right side.

Divide $48$ by $8$ .

$y = 6$

The solution to the independent system of equations can be represented as a point.

$(- 7, 6)$

The result can be shown in multiple forms.

Point Form:

$(- 7, 6)$

Equation Form:

$x = - 7, y = 6$

Solve by Addition/Elimination 6x-6=-8y , 5x+4y=-11

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