Solve by Addition/Elimination -8x+3y=3 13x-3y=-18

$- 8 x + 3 y = 3$ $13 x - 3 y = - 18$

Step 1

Add the two equations together to eliminate $y$ from the system.

	$-$	$8$	$x$	$+$	$3$	$y$	$=$			$3$
$+$	$1$	$3$	$x$	$-$	$3$	$y$	$=$	$-$	$1$	$8$
		$5$	$x$				$=$	$-$	$1$	$5$

Step 2

Divide each term in $5 x = - 15$ by $5$ and simplify.

Divide each term in $5 x = - 15$ by $5$ .

$\frac{5 x}{5} = \frac{- 15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{- 15}{5}$

Divide $x$ by $1$ .

$x = \frac{- 15}{5}$

Simplify the right side.

Divide $- 15$ by $5$ .

$x = - 3$

Step 3

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$- 8 \cdot - 3 + 3 y = 3$

Multiply $- 8$ by $- 3$ .

$24 + 3 y = 3$

Move all terms not containing $y$ to the right side of the equation.

Subtract $24$ from both sides of the equation.

$3 y = 3 - 24$

Subtract $24$ from $3$ .

$3 y = - 21$

Divide each term in $3 y = - 21$ by $3$ and simplify.

Divide each term in $3 y = - 21$ by $3$ .

$\frac{3 y}{3} = \frac{- 21}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 y}{3} = \frac{- 21}{3}$

Divide $y$ by $1$ .

$y = \frac{- 21}{3}$

Simplify the right side.

Divide $- 21$ by $3$ .

$y = - 7$

Step 4

The solution to the independent system of equations can be represented as a point.

$(- 3, - 7)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(- 3, - 7)$

Equation Form:

$x = - 3, y = - 7$

Step 6

Solve by Addition/Elimination -8x+3y=3 13x-3y=-18

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