Solve by Addition/Elimination x+2y=13 4x+8y=-9

$x + 2 y = 13$ $4 x + 8 y = - 9$

Step 1

Multiply each equation by the value that makes the coefficients of $x$ opposite.

$(- 4) \cdot (x + 2 y) = (- 4) (13)$

$4 x + 8 y = - 9$

Step 2

Simplify.

Simplify the left side.

Simplify $(- 4) \cdot (x + 2 y)$ .

Apply the distributive property.

$- 4 x - 4 (2 y) = (- 4) (13)$

$4 x + 8 y = - 9$

Multiply $2$ by $- 4$ .

$- 4 x - 8 y = (- 4) (13)$

$4 x + 8 y = - 9$

$- 4 x - 8 y = (- 4) (13)$

$4 x + 8 y = - 9$

$- 4 x - 8 y = (- 4) (13)$

$4 x + 8 y = - 9$

Simplify the right side.

Multiply $- 4$ by $13$ .

$- 4 x - 8 y = - 52$

$4 x + 8 y = - 9$

$- 4 x - 8 y = - 52$

$4 x + 8 y = - 9$

$- 4 x - 8 y = - 52$

$4 x + 8 y = - 9$

Step 3

Add the two equations together to eliminate $x$ from the system.

Step 4

Since $0 \neq - 61$ , there are no solutions.

No solution

Step 5