Solve by Addition/Elimination x-y=-3 2x+y=18

$x - y = - 3$ $2 x + y = 18$

Step 1

Add the two equations together to eliminate $y$ from the system.

		$x$	$-$	$y$	$=$	$-$	$3$
$+$	$2$	$x$	$+$	$y$	$=$	$1$	$8$
	$3$	$x$			$=$	$1$	$5$

Step 2

Divide each term in $3 x = 15$ by $3$ and simplify.

Divide each term in $3 x = 15$ by $3$ .

$\frac{3 x}{3} = \frac{15}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{15}{3}$

Divide $x$ by $1$ .

$x = \frac{15}{3}$

Simplify the right side.

Divide $15$ by $3$ .

$x = 5$

Step 3

Substitute the value found for $x$ into one of the original equations, then solve for $y$ .

Substitute the value found for $x$ into one of the original equations to solve for $y$ .

$(5) - y = - 3$

Remove parentheses.

$5 - y = - 3$

Move all terms not containing $y$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$- y = - 3 - 5$

Subtract $5$ from $- 3$ .

$- y = - 8$

Divide each term in $- y = - 8$ by $- 1$ and simplify.

Divide each term in $- y = - 8$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 8}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 8}{- 1}$

Divide $y$ by $1$ .

$y = \frac{- 8}{- 1}$

Simplify the right side.

Divide $- 8$ by $- 1$ .

$y = 8$

Step 4

The solution to the independent system of equations can be represented as a point.

$(5, 8)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(5, 8)$

Equation Form:

$x = 5, y = 8$

Step 6

Solve by Addition/Elimination x-y=-3 2x+y=18

Related Questions

Support LCMGCF.com by disabling your adblocker.