Solve by Addition/Elimination -x+y=4 x+3y=4

$- x + y = 4$ $x + 3 y = 4$

Add the two equations together to eliminate $x$ from the system.

Divide each term in $4 y = 8$ by $4$ and simplify.

Divide each term in $4 y = 8$ by $4$ .

$\frac{4 y}{4} = \frac{8}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{8}{4}$

Divide $y$ by $1$ .

$y = \frac{8}{4}$

Simplify the right side.

Divide $8$ by $4$ .

$y = 2$

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$- x + 2 = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$- x = 4 - 2$

Subtract $2$ from $4$ .

$- x = 2$

Divide each term in $- x = 2$ by $- 1$ and simplify.

Divide each term in $- x = 2$ by $- 1$ .

$\frac{- x}{- 1} = \frac{2}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{2}{- 1}$

Divide $x$ by $1$ .

$x = \frac{2}{- 1}$

Simplify the right side.

Divide $2$ by $- 1$ .

$x = - 2$

The solution to the independent system of equations can be represented as a point.

$(- 2, 2)$

The result can be shown in multiple forms.

Point Form:

$(- 2, 2)$

Equation Form:

$x = - 2, y = 2$