Solve by Addition/Elimination x+y=4 , x-y=2

$x + y = 4$ , $x - y = 2$

Multiply each equation by the value that makes the coefficients of $x$ opposite.

$x + y = 4$

$(- 1) \cdot (x - y) = (- 1) (2)$

Simplify.

Simplify the left side.

Simplify $(- 1) \cdot (x - y)$ .

Apply the distributive property.

$x + y = 4$

$- 1 x - 1 (- y) = (- 1) (2)$

Rewrite $- 1 x$ as $- x$ .

$x + y = 4$

$- x - 1 (- y) = (- 1) (2)$

Multiply $- 1 (- y)$ .

Multiply $- 1$ by $- 1$ .

$x + y = 4$

$- x + 1 y = (- 1) (2)$

Multiply $y$ by $1$ .

$x + y = 4$

$- x + y = (- 1) (2)$

$x + y = 4$

$- x + y = (- 1) (2)$

$x + y = 4$

$- x + y = (- 1) (2)$

$x + y = 4$

$- x + y = (- 1) (2)$

Simplify the right side.

Multiply $- 1$ by $2$ .

$x + y = 4$

$- x + y = - 2$

$x + y = 4$

$- x + y = - 2$

$x + y = 4$

$- x + y = - 2$

Add the two equations together to eliminate $x$ from the system.

		$x$	$+$	$y$	$=$		$4$
$+$	$-$	$x$	$+$	$y$	$=$	$-$	$2$
			$2$	$y$	$=$		$2$

Divide each term in $2 y = 2$ by $2$ and simplify.

Divide each term in $2 y = 2$ by $2$ .

$\frac{2 y}{2} = \frac{2}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 y}{2} = \frac{2}{2}$

Divide $y$ by $1$ .

$y = \frac{2}{2}$

Simplify the right side.

Divide $2$ by $2$ .

$y = 1$

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$x + 1 = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 4 - 1$

Subtract $1$ from $4$ .

$x = 3$

The solution to the independent system of equations can be represented as a point.

$(3, 1)$

The result can be shown in multiple forms.

Point Form:

$(3, 1)$

Equation Form:

$x = 3, y = 1$

Solve by Addition/Elimination x+y=4 , x-y=2

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