Solve by Addition/Elimination x+y=6 -x+3y=-2

$x + y = 6$ $- x + 3 y = - 2$

Step 1

Add the two equations together to eliminate $x$ from the system.

Step 2

Divide each term in $4 y = 4$ by $4$ and simplify.

Divide each term in $4 y = 4$ by $4$ .

$\frac{4 y}{4} = \frac{4}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 y}{4} = \frac{4}{4}$

Divide $y$ by $1$ .

$y = \frac{4}{4}$

Simplify the right side.

Divide $4$ by $4$ .

$y = 1$

Step 3

Substitute the value found for $y$ into one of the original equations, then solve for $x$ .

Substitute the value found for $y$ into one of the original equations to solve for $x$ .

$x + 1 = 6$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 6 - 1$

Subtract $1$ from $6$ .

$x = 5$

Step 4

The solution to the independent system of equations can be represented as a point.

$(5, 1)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(5, 1)$

Equation Form:

$x = 5, y = 1$

Step 6