Solve by Completing the Square 2x^2-12x+4=0

$2 x^{2} - 12 x + 4 = 0$

Step 1

Subtract $4$ from both sides of the equation.

$2 x^{2} - 12 x = - 4$

Step 2

Divide each term in $2 x^{2} - 12 x = - 4$ by $2$ and simplify.

Divide each term in $2 x^{2} - 12 x = - 4$ by $2$ .

$\frac{2 x^{2}}{2} + \frac{- 12 x}{2} = \frac{- 4}{2}$

Simplify the left side.

Simplify each term.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x^{2}}{2} + \frac{- 12 x}{2} = \frac{- 4}{2}$

Divide $x^{2}$ by $1$ .

$x^{2} + \frac{- 12 x}{2} = \frac{- 4}{2}$

Cancel the common factor of $- 12$ and $2$ .

Factor $2$ out of $- 12 x$ .

$x^{2} + \frac{2 (- 6 x)}{2} = \frac{- 4}{2}$

Cancel the common factors.

Factor $2$ out of $2$ .

$x^{2} + \frac{2 (- 6 x)}{2 (1)} = \frac{- 4}{2}$

Cancel the common factor.

$x^{2} + \frac{2 (- 6 x)}{2 \cdot 1} = \frac{- 4}{2}$

Rewrite the expression.

$x^{2} + \frac{- 6 x}{1} = \frac{- 4}{2}$

Divide $- 6 x$ by $1$ .

$x^{2} - 6 x = \frac{- 4}{2}$

Simplify the right side.

Divide $- 4$ by $2$ .

$x^{2} - 6 x = - 2$

Step 3

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(- 3)}^{2}$

Step 4

Add the term to each side of the equation.

$x^{2} - 6 x + {(- 3)}^{2} = - 2 + {(- 3)}^{2}$

Step 5

Simplify the equation.

Simplify the left side.

Raise $- 3$ to the power of $2$ .

$x^{2} - 6 x + 9 = - 2 + {(- 3)}^{2}$

Simplify the right side.

Simplify $- 2 + {(- 3)}^{2}$ .

Raise $- 3$ to the power of $2$ .

$x^{2} - 6 x + 9 = - 2 + 9$

Add $- 2$ and $9$ .

$x^{2} - 6 x + 9 = 7$

Step 6

Factor the perfect trinomial square into ${(x - 3)}^{2}$ .

${(x - 3)}^{2} = 7$

Step 7

Solve the equation for $x$ .

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x - 3 = \pm \sqrt{7}$

Add $3$ to both sides of the equation.

$x = \pm \sqrt{7} + 3$

Step 8

The result can be shown in multiple forms.

Exact Form:

$x = \pm \sqrt{7} + 3$

Decimal Form:

$x = 5.64575131 \dots, 0.35424868 \dots$

Solve by Completing the Square 2x^2-12x+4=0

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