Solve by Completing the Square 4x^2+x-1/8=0

$4 x^{2} + x - \frac{1}{8} = 0$

Step 1

Add $\frac{1}{8}$ to both sides of the equation.

$4 x^{2} + x = \frac{1}{8}$

Step 2

Divide each term in $4 x^{2} + x = \frac{1}{8}$ by $4$ and simplify.

Divide each term in $4 x^{2} + x = \frac{1}{8}$ by $4$ .

$\frac{4 x^{2}}{4} + \frac{x}{4} = \frac{\frac{1}{8}}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x^{2}}{4} + \frac{x}{4} = \frac{\frac{1}{8}}{4}$

Divide $x^{2}$ by $1$ .

$x^{2} + \frac{x}{4} = \frac{\frac{1}{8}}{4}$

Simplify the right side.

Multiply the numerator by the reciprocal of the denominator.

$x^{2} + \frac{x}{4} = \frac{1}{8} \cdot \frac{1}{4}$

Multiply $\frac{1}{8} \cdot \frac{1}{4}$ .

Multiply $\frac{1}{8}$ by $\frac{1}{4}$ .

$x^{2} + \frac{x}{4} = \frac{1}{8 \cdot 4}$

Multiply $8$ by $4$ .

$x^{2} + \frac{x}{4} = \frac{1}{32}$

Step 3

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(\frac{1}{8})}^{2}$

Step 4

Add the term to each side of the equation.

$x^{2} + \frac{x}{4} + {(\frac{1}{8})}^{2} = \frac{1}{32} + {(\frac{1}{8})}^{2}$

Step 5

Simplify the equation.

Simplify the left side.

Simplify each term.

Apply the product rule to $\frac{1}{8}$ .

$x^{2} + \frac{x}{4} + \frac{1^{2}}{8^{2}} = \frac{1}{32} + {(\frac{1}{8})}^{2}$

One to any power is one.

$x^{2} + \frac{x}{4} + \frac{1}{8^{2}} = \frac{1}{32} + {(\frac{1}{8})}^{2}$

Raise $8$ to the power of $2$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{1}{32} + {(\frac{1}{8})}^{2}$

Simplify the right side.

Simplify $\frac{1}{32} + {(\frac{1}{8})}^{2}$ .

Simplify each term.

Apply the product rule to $\frac{1}{8}$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{1}{32} + \frac{1^{2}}{8^{2}}$

One to any power is one.

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{1}{32} + \frac{1}{8^{2}}$

Raise $8$ to the power of $2$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{1}{32} + \frac{1}{64}$

To write $\frac{1}{32}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{1}{32} \cdot \frac{2}{2} + \frac{1}{64}$

Write each expression with a common denominator of $64$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{32}$ by $\frac{2}{2}$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{2}{32 \cdot 2} + \frac{1}{64}$

Multiply $32$ by $2$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{2}{64} + \frac{1}{64}$

Combine the numerators over the common denominator.

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{2 + 1}{64}$

Add $2$ and $1$ .

$x^{2} + \frac{x}{4} + \frac{1}{64} = \frac{3}{64}$

Step 6

Factor the perfect trinomial square into ${(x + \frac{1}{8})}^{2}$ .

${(x + \frac{1}{8})}^{2} = \frac{3}{64}$

Step 7

Solve the equation for $x$ .

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + \frac{1}{8} = \pm \sqrt{\frac{3}{64}}$

Simplify $\pm \sqrt{\frac{3}{64}}$ .

Rewrite $\sqrt{\frac{3}{64}}$ as $\frac{\sqrt{3}}{\sqrt{64}}$ .

$x + \frac{1}{8} = \pm \frac{\sqrt{3}}{\sqrt{64}}$

Simplify the denominator.

Rewrite $64$ as $8^{2}$ .

$x + \frac{1}{8} = \pm \frac{\sqrt{3}}{\sqrt{8^{2}}}$

Pull terms out from under the radical, assuming positive real numbers.

$x + \frac{1}{8} = \pm \frac{\sqrt{3}}{8}$

Subtract $\frac{1}{8}$ from both sides of the equation.

$x = \pm \frac{\sqrt{3}}{8} - \frac{1}{8}$

Step 8

The result can be shown in multiple forms.

Exact Form:

$x = \pm \frac{\sqrt{3}}{8} - \frac{1}{8}$

Decimal Form:

$x = 0.09150635 \dots, - 0.34150635 \dots$

Solve by Completing the Square 4x^2+x-1/8=0

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