Solve by Factoring 1/(x+2)-1/(x-2)=0

$\frac{1}{x + 2} - \frac{1}{x - 2} = 0$

Step 1

To write $\frac{1}{x + 2}$ as a fraction with a common denominator, multiply by $\frac{x - 2}{x - 2}$ .

$\frac{1}{x + 2} \cdot \frac{x - 2}{x - 2} - \frac{1}{x - 2} = 0$

Step 2

To write $- \frac{1}{x - 2}$ as a fraction with a common denominator, multiply by $\frac{x + 2}{x + 2}$ .

$\frac{1}{x + 2} \cdot \frac{x - 2}{x - 2} - \frac{1}{x - 2} \cdot \frac{x + 2}{x + 2} = 0$

Step 3

Write each expression with a common denominator of $(x + 2) (x - 2)$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{x + 2}$ by $\frac{x - 2}{x - 2}$ .

$\frac{x - 2}{(x + 2) (x - 2)} - \frac{1}{x - 2} \cdot \frac{x + 2}{x + 2} = 0$

Multiply $\frac{1}{x - 2}$ by $\frac{x + 2}{x + 2}$ .

$\frac{x - 2}{(x + 2) (x - 2)} - \frac{x + 2}{(x - 2) (x + 2)} = 0$

Reorder the factors of $(x - 2) (x + 2)$ .

$\frac{x - 2}{(x + 2) (x - 2)} - \frac{x + 2}{(x + 2) (x - 2)} = 0$

Step 4

Combine the numerators over the common denominator.

$\frac{x - 2 - (x + 2)}{(x + 2) (x - 2)} = 0$

Step 5

Rewrite $\frac{x - 2 - (x + 2)}{(x + 2) (x - 2)}$ in a factored form.

Apply the distributive property.

$\frac{x - 2 - x - 1 \cdot 2}{(x + 2) (x - 2)} = 0$

Multiply $- 1$ by $2$ .

$\frac{x - 2 - x - 2}{(x + 2) (x - 2)} = 0$

Subtract $x$ from $x$ .

$\frac{0 - 2 - 2}{(x + 2) (x - 2)} = 0$

Subtract $2$ from $0$ .

$\frac{- 2 - 2}{(x + 2) (x - 2)} = 0$

Subtract $2$ from $- 2$ .

$\frac{- 4}{(x + 2) (x - 2)} = 0$

Step 6

Move the negative in front of the fraction.

$- \frac{4}{(x + 2) (x - 2)} = 0$

Step 7

Set the numerator equal to zero.

$4 = 0$

Step 8

Since $4 \neq 0$ , there are no solutions.

No solution