Solve by Factoring 1/(x-4)-4/(x^2-4x)=2

$\frac{1}{x - 4} - \frac{4}{x^{2} - 4 x} = 2$

Step 1

Subtract $2$ from both sides of the equation.

$\frac{1}{x - 4} - \frac{4}{x^{2} - 4 x} - 2 = 0$

Step 2

Simplify $\frac{1}{x - 4} - \frac{4}{x^{2} - 4 x} - 2$ .

Factor $x$ out of $x^{2} - 4 x$ .

Factor $x$ out of $x^{2}$ .

$\frac{1}{x - 4} - \frac{4}{x \cdot x - 4 x} - 2 = 0$

Factor $x$ out of $- 4 x$ .

$\frac{1}{x - 4} - \frac{4}{x \cdot x + x \cdot - 4} - 2 = 0$

Factor $x$ out of $x \cdot x + x \cdot - 4$ .

$\frac{1}{x - 4} - \frac{4}{x (x - 4)} - 2 = 0$

To write $\frac{1}{x - 4}$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{1}{x - 4} \cdot \frac{x}{x} - \frac{4}{x (x - 4)} - 2 = 0$

Write each expression with a common denominator of $(x - 4) x$ , by multiplying each by an appropriate factor of $1$ .

Multiply $\frac{1}{x - 4}$ by $\frac{x}{x}$ .

$\frac{x}{(x - 4) x} - \frac{4}{x (x - 4)} - 2 = 0$

Reorder the factors of $(x - 4) x$ .

$\frac{x}{x (x - 4)} - \frac{4}{x (x - 4)} - 2 = 0$

Combine the numerators over the common denominator.

$\frac{x - 4}{x (x - 4)} - 2 = 0$

Cancel the common factor of $x - 4$ .

Cancel the common factor.

$\frac{x - 4}{x (x - 4)} - 2 = 0$

Rewrite the expression.

$\frac{1}{x} - 2 = 0$

Step 3

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{x}{x}$ .

$\frac{1}{x} - 2 \cdot \frac{x}{x} = 0$

Step 4

Combine $- 2$ and $\frac{x}{x}$ .

$\frac{1}{x} + \frac{- 2 x}{x} = 0$

Step 5

Combine the numerators over the common denominator.

$\frac{1 - 2 x}{x} = 0$

Step 6

Set the numerator equal to zero.

$1 - 2 x = 0$

Step 7

Solve the equation for $x$ .

Subtract $1$ from both sides of the equation.

$- 2 x = - 1$

Divide each term in $- 2 x = - 1$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 1$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 1}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 1}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 1}{- 2}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{1}{2}$

Solve by Factoring 1/(x-4)-4/(x^2-4x)=2

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