Solve by Factoring 125x^3-27=0

$125 x^{3} - 27 = 0$

Step 1

Rewrite $125 x^{3}$ as ${(5 x)}^{3}$ .

${(5 x)}^{3} - 27 = 0$

Step 2

Rewrite $27$ as $3^{3}$ .

${(5 x)}^{3} - 3^{3} = 0$

Step 3

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 5 x$ and $b = 3$ .

$(5 x - 3) ({(5 x)}^{2} + 5 x \cdot 3 + 3^{2}) = 0$

Step 4

Simplify.

Apply the product rule to $5 x$ .

$(5 x - 3) (5^{2} x^{2} + 5 x \cdot 3 + 3^{2}) = 0$

Raise $5$ to the power of $2$ .

$(5 x - 3) (25 x^{2} + 5 x \cdot 3 + 3^{2}) = 0$

Multiply $3$ by $5$ .

$(5 x - 3) (25 x^{2} + 15 x + 3^{2}) = 0$

Raise $3$ to the power of $2$ .

$(5 x - 3) (25 x^{2} + 15 x + 9) = 0$

Step 5

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$5 x - 3 = 0$

$25 x^{2} + 15 x + 9 = 0$

Step 6

Set $5 x - 3$ equal to $0$ and solve for $x$ .

Set $5 x - 3$ equal to $0$ .

$5 x - 3 = 0$

Solve $5 x - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$5 x = 3$

Divide each term in $5 x = 3$ by $5$ and simplify.

Divide each term in $5 x = 3$ by $5$ .

$\frac{5 x}{5} = \frac{3}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{3}{5}$

Divide $x$ by $1$ .

$x = \frac{3}{5}$

Step 7

Set $25 x^{2} + 15 x + 9$ equal to $0$ and solve for $x$ .

Set $25 x^{2} + 15 x + 9$ equal to $0$ .

$25 x^{2} + 15 x + 9 = 0$

Solve $25 x^{2} + 15 x + 9 = 0$ for $x$ .

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Substitute the values $a = 25$ , $b = 15$ , and $c = 9$ into the quadratic formula and solve for $x$ .

$\frac{- 15 \pm \sqrt{15^{2} - 4 \cdot (25 \cdot 9)}}{2 \cdot 25}$

Simplify.

Simplify the numerator.

Raise $15$ to the power of $2$ .

$x = \frac{- 15 \pm \sqrt{225 - 4 \cdot 25 \cdot 9}}{2 \cdot 25}$

Multiply $- 4 \cdot 25 \cdot 9$ .

Multiply $- 4$ by $25$ .

$x = \frac{- 15 \pm \sqrt{225 - 100 \cdot 9}}{2 \cdot 25}$

Multiply $- 100$ by $9$ .

$x = \frac{- 15 \pm \sqrt{225 - 900}}{2 \cdot 25}$

Subtract $900$ from $225$ .

$x = \frac{- 15 \pm \sqrt{- 675}}{2 \cdot 25}$

Rewrite $- 675$ as $- 1 (675)$ .

$x = \frac{- 15 \pm \sqrt{- 1 \cdot 675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1 (675)}$ as $\sqrt{- 1} \cdot \sqrt{675}$ .

$x = \frac{- 15 \pm \sqrt{- 1} \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 15 \pm i \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $675$ as $15^{2} \cdot 3$ .

Factor $225$ out of $675$ .

$x = \frac{- 15 \pm i \cdot \sqrt{225 (3)}}{2 \cdot 25}$

Rewrite $225$ as $15^{2}$ .

$x = \frac{- 15 \pm i \cdot \sqrt{15^{2} \cdot 3}}{2 \cdot 25}$

Pull terms out from under the radical.

$x = \frac{- 15 \pm i \cdot (15 \sqrt{3})}{2 \cdot 25}$

Move $15$ to the left of $i$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{2 \cdot 25}$

Multiply $2$ by $25$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{50}$

Simplify $\frac{- 15 \pm 15 i \sqrt{3}}{50}$ .

$x = \frac{- 3 \pm 3 i \sqrt{3}}{10}$

Simplify the expression to solve for the $+$ portion of the $\pm$ .

Simplify the numerator.

Raise $15$ to the power of $2$ .

$x = \frac{- 15 \pm \sqrt{225 - 4 \cdot 25 \cdot 9}}{2 \cdot 25}$

Multiply $- 4 \cdot 25 \cdot 9$ .

Multiply $- 4$ by $25$ .

$x = \frac{- 15 \pm \sqrt{225 - 100 \cdot 9}}{2 \cdot 25}$

Multiply $- 100$ by $9$ .

$x = \frac{- 15 \pm \sqrt{225 - 900}}{2 \cdot 25}$

Subtract $900$ from $225$ .

$x = \frac{- 15 \pm \sqrt{- 675}}{2 \cdot 25}$

Rewrite $- 675$ as $- 1 (675)$ .

$x = \frac{- 15 \pm \sqrt{- 1 \cdot 675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1 (675)}$ as $\sqrt{- 1} \cdot \sqrt{675}$ .

$x = \frac{- 15 \pm \sqrt{- 1} \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 15 \pm i \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $675$ as $15^{2} \cdot 3$ .

Factor $225$ out of $675$ .

$x = \frac{- 15 \pm i \cdot \sqrt{225 (3)}}{2 \cdot 25}$

Rewrite $225$ as $15^{2}$ .

$x = \frac{- 15 \pm i \cdot \sqrt{15^{2} \cdot 3}}{2 \cdot 25}$

Pull terms out from under the radical.

$x = \frac{- 15 \pm i \cdot (15 \sqrt{3})}{2 \cdot 25}$

Move $15$ to the left of $i$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{2 \cdot 25}$

Multiply $2$ by $25$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{50}$

Simplify $\frac{- 15 \pm 15 i \sqrt{3}}{50}$ .

$x = \frac{- 3 \pm 3 i \sqrt{3}}{10}$

Change the $\pm$ to $+$ .

$x = \frac{- 3 + 3 i \sqrt{3}}{10}$

Rewrite $- 3$ as $- 1 (3)$ .

$x = \frac{- 1 \cdot 3 + 3 i \sqrt{3}}{10}$

Factor $- 1$ out of $3 i \sqrt{3}$ .

$x = \frac{- 1 \cdot 3 - (- 3 i \sqrt{3})}{10}$

Factor $- 1$ out of $- 1 (3) - (- 3 i \sqrt{3})$ .

$x = \frac{- 1 (3 - 3 i \sqrt{3})}{10}$

Move the negative in front of the fraction.

$x = - \frac{3 - 3 i \sqrt{3}}{10}$

Simplify the expression to solve for the $-$ portion of the $\pm$ .

Simplify the numerator.

Raise $15$ to the power of $2$ .

$x = \frac{- 15 \pm \sqrt{225 - 4 \cdot 25 \cdot 9}}{2 \cdot 25}$

Multiply $- 4 \cdot 25 \cdot 9$ .

Multiply $- 4$ by $25$ .

$x = \frac{- 15 \pm \sqrt{225 - 100 \cdot 9}}{2 \cdot 25}$

Multiply $- 100$ by $9$ .

$x = \frac{- 15 \pm \sqrt{225 - 900}}{2 \cdot 25}$

Subtract $900$ from $225$ .

$x = \frac{- 15 \pm \sqrt{- 675}}{2 \cdot 25}$

Rewrite $- 675$ as $- 1 (675)$ .

$x = \frac{- 15 \pm \sqrt{- 1 \cdot 675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1 (675)}$ as $\sqrt{- 1} \cdot \sqrt{675}$ .

$x = \frac{- 15 \pm \sqrt{- 1} \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $\sqrt{- 1}$ as $i$ .

$x = \frac{- 15 \pm i \cdot \sqrt{675}}{2 \cdot 25}$

Rewrite $675$ as $15^{2} \cdot 3$ .

Factor $225$ out of $675$ .

$x = \frac{- 15 \pm i \cdot \sqrt{225 (3)}}{2 \cdot 25}$

Rewrite $225$ as $15^{2}$ .

$x = \frac{- 15 \pm i \cdot \sqrt{15^{2} \cdot 3}}{2 \cdot 25}$

Pull terms out from under the radical.

$x = \frac{- 15 \pm i \cdot (15 \sqrt{3})}{2 \cdot 25}$

Move $15$ to the left of $i$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{2 \cdot 25}$

Multiply $2$ by $25$ .

$x = \frac{- 15 \pm 15 i \sqrt{3}}{50}$

Simplify $\frac{- 15 \pm 15 i \sqrt{3}}{50}$ .

$x = \frac{- 3 \pm 3 i \sqrt{3}}{10}$

Change the $\pm$ to $-$ .

$x = \frac{- 3 - 3 i \sqrt{3}}{10}$

Rewrite $- 3$ as $- 1 (3)$ .

$x = \frac{- 1 \cdot 3 - 3 i \sqrt{3}}{10}$

Factor $- 1$ out of $- 3 i \sqrt{3}$ .

$x = \frac{- 1 \cdot 3 - (3 i \sqrt{3})}{10}$

Factor $- 1$ out of $- 1 (3) - (3 i \sqrt{3})$ .

$x = \frac{- 1 (3 + 3 i \sqrt{3})}{10}$

Move the negative in front of the fraction.

$x = - \frac{3 + 3 i \sqrt{3}}{10}$

The final answer is the combination of both solutions.

$x = - \frac{3 - 3 i \sqrt{3}}{10}, - \frac{3 + 3 i \sqrt{3}}{10}$

Step 8

The final solution is all the values that make $(5 x - 3) (25 x^{2} + 15 x + 9) = 0$ true.

$x = \frac{3}{5}, - \frac{3 - 3 i \sqrt{3}}{10}, - \frac{3 + 3 i \sqrt{3}}{10}$

Solve by Factoring 125x^3-27=0

Related Questions

Support LCMGCF.com by disabling your adblocker.