Solve by Factoring 12y+6=6(2y+1)

$12 y + 6 = 6 (2 y + 1)$

Step 1

Subtract $6 (2 y + 1)$ from both sides of the equation.

$12 y + 6 - 6 (2 y + 1) = 0$

Step 2

Simplify $12 y + 6 - 6 (2 y + 1)$ .

Simplify each term.

Apply the distributive property.

$12 y + 6 - 6 (2 y) - 6 \cdot 1 = 0$

Multiply $2$ by $- 6$ .

$12 y + 6 - 12 y - 6 \cdot 1 = 0$

Multiply $- 6$ by $1$ .

$12 y + 6 - 12 y - 6 = 0$

Combine the opposite terms in $12 y + 6 - 12 y - 6$ .

Subtract $12 y$ from $12 y$ .

$0 + 6 - 6 = 0$

Add $0$ and $6$ .

$6 - 6 = 0$

Subtract $6$ from $6$ .

$0 = 0$

Step 3

Since $0 = 0$ , the equation will always be true.

Always true