Solve by Factoring 16x^2-36=0

$16 x^{2} - 36 = 0$

Step 1

Factor $4$ out of $16 x^{2} - 36$ .

Factor $4$ out of $16 x^{2}$ .

$4 (4 x^{2}) - 36 = 0$

Factor $4$ out of $- 36$ .

$4 (4 x^{2}) + 4 (- 9) = 0$

Factor $4$ out of $4 (4 x^{2}) + 4 (- 9)$ .

$4 (4 x^{2} - 9) = 0$

Step 2

Rewrite $4 x^{2}$ as ${(2 x)}^{2}$ .

$4 ({(2 x)}^{2} - 9) = 0$

Step 3

Rewrite $9$ as $3^{2}$ .

$4 ({(2 x)}^{2} - 3^{2}) = 0$

Step 4

Factor.

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 2 x$ and $b = 3$ .

$4 ((2 x + 3) (2 x - 3)) = 0$

Remove unnecessary parentheses.

$4 (2 x + 3) (2 x - 3) = 0$

Step 5

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 3 = 0$

$2 x - 3 = 0$

Step 6

Set $2 x + 3$ equal to $0$ and solve for $x$ .

Set $2 x + 3$ equal to $0$ .

$2 x + 3 = 0$

Solve $2 x + 3 = 0$ for $x$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

Step 7

Set $2 x - 3$ equal to $0$ and solve for $x$ .

Set $2 x - 3$ equal to $0$ .

$2 x - 3 = 0$

Solve $2 x - 3 = 0$ for $x$ .

Add $3$ to both sides of the equation.

$2 x = 3$

Divide each term in $2 x = 3$ by $2$ and simplify.

Divide each term in $2 x = 3$ by $2$ .

$\frac{2 x}{2} = \frac{3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{3}{2}$

Divide $x$ by $1$ .

$x = \frac{3}{2}$

Step 8

The final solution is all the values that make $4 (2 x + 3) (2 x - 3) = 0$ true.

$x = - \frac{3}{2}, \frac{3}{2}$

Solve by Factoring 16x^2-36=0

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