Solve by Factoring 25x^2+49=70x

$25 x^{2} + 49 = 70 x$

Subtract $70 x$ from both sides of the equation.

$25 x^{2} + 49 - 70 x = 0$

Factor using the perfect square rule.

Rearrange terms.

$25 x^{2} - 70 x + 49 = 0$

Rewrite $25 x^{2}$ as ${(5 x)}^{2}$ .

${(5 x)}^{2} - 70 x + 49 = 0$

Rewrite $49$ as $7^{2}$ .

${(5 x)}^{2} - 70 x + 7^{2} = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$70 x = 2 \cdot (5 x) \cdot 7$

Rewrite the polynomial.

${(5 x)}^{2} - 2 \cdot (5 x) \cdot 7 + 7^{2} = 0$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = 5 x$ and $b = 7$ .

${(5 x - 7)}^{2} = 0$

Set the $5 x - 7$ equal to $0$ .

$5 x - 7 = 0$

Solve for $x$ .

Add $7$ to both sides of the equation.

$5 x = 7$

Divide each term in $5 x = 7$ by $5$ and simplify.

Divide each term in $5 x = 7$ by $5$ .

$\frac{5 x}{5} = \frac{7}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} = \frac{7}{5}$

Divide $x$ by $1$ .

$x = \frac{7}{5}$