Solve by Factoring 2x^2-15x=8

$2 x^{2} - 15 x = 8$

Step 1

Subtract $8$ from both sides of the equation.

$2 x^{2} - 15 x - 8 = 0$

Step 2

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 8 = - 16$ and whose sum is $b = - 15$ .

Factor $- 15$ out of $- 15 x$ .

$2 x^{2} - 15 x - 8 = 0$

Rewrite $- 15$ as $1$ plus $- 16$

$2 x^{2} + (1 - 16) x - 8 = 0$

Apply the distributive property.

$2 x^{2} + 1 x - 16 x - 8 = 0$

Multiply $x$ by $1$ .

$2 x^{2} + x - 16 x - 8 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(2 x^{2} + x) - 16 x - 8 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (2 x + 1) - 8 (2 x + 1) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x + 1$ .

$(2 x + 1) (x - 8) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 1 = 0$

$x - 8 = 0$

Step 4

Set $2 x + 1$ equal to $0$ and solve for $x$ .

Set $2 x + 1$ equal to $0$ .

$2 x + 1 = 0$

Solve $2 x + 1 = 0$ for $x$ .

Subtract $1$ from both sides of the equation.

$2 x = - 1$

Divide each term in $2 x = - 1$ by $2$ and simplify.

Divide each term in $2 x = - 1$ by $2$ .

$\frac{2 x}{2} = \frac{- 1}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 1}{2}$

Divide $x$ by $1$ .

$x = \frac{- 1}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{1}{2}$

Step 5

Set $x - 8$ equal to $0$ and solve for $x$ .

Set $x - 8$ equal to $0$ .

$x - 8 = 0$

Add $8$ to both sides of the equation.

$x = 8$

Step 6

The final solution is all the values that make $(2 x + 1) (x - 8) = 0$ true.

$x = - \frac{1}{2}, 8$

Solve by Factoring 2x^2-15x=8

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