Solve by Factoring 2x^2=19x+33

$2 x^{2} = 19 x + 33$

Step 1

Move all the expressions to the left side of the equation.

Subtract $19 x$ from both sides of the equation.

$2 x^{2} - 19 x = 33$

Subtract $33$ from both sides of the equation.

$2 x^{2} - 19 x - 33 = 0$

Step 2

Factor by grouping.

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = 2 \cdot - 33 = - 66$ and whose sum is $b = - 19$ .

Factor $- 19$ out of $- 19 x$ .

$2 x^{2} - 19 x - 33 = 0$

Rewrite $- 19$ as $3$ plus $- 22$

$2 x^{2} + (3 - 22) x - 33 = 0$

Apply the distributive property.

$2 x^{2} + 3 x - 22 x - 33 = 0$

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

$(2 x^{2} + 3 x) - 22 x - 33 = 0$

Factor out the greatest common factor (GCF) from each group.

$x (2 x + 3) - 11 (2 x + 3) = 0$

Factor the polynomial by factoring out the greatest common factor, $2 x + 3$ .

$(2 x + 3) (x - 11) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$2 x + 3 = 0$

$x - 11 = 0$

Step 4

Set $2 x + 3$ equal to $0$ and solve for $x$ .

Set $2 x + 3$ equal to $0$ .

$2 x + 3 = 0$

Solve $2 x + 3 = 0$ for $x$ .

Subtract $3$ from both sides of the equation.

$2 x = - 3$

Divide each term in $2 x = - 3$ by $2$ and simplify.

Divide each term in $2 x = - 3$ by $2$ .

$\frac{2 x}{2} = \frac{- 3}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{- 3}{2}$

Divide $x$ by $1$ .

$x = \frac{- 3}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{3}{2}$

Step 5

Set $x - 11$ equal to $0$ and solve for $x$ .

Set $x - 11$ equal to $0$ .

$x - 11 = 0$

Add $11$ to both sides of the equation.

$x = 11$

Step 6

The final solution is all the values that make $(2 x + 3) (x - 11) = 0$ true.

$x = - \frac{3}{2}, 11$

Solve by Factoring 2x^2=19x+33

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