Solve by Factoring 2x^2=8x

$2 x^{2} = 8 x$

Step 1

Subtract $8 x$ from both sides of the equation.

$2 x^{2} - 8 x = 0$

Step 2

Factor $2 x$ out of $2 x^{2} - 8 x$ .

Factor $2 x$ out of $2 x^{2}$ .

$2 x (x) - 8 x = 0$

Factor $2 x$ out of $- 8 x$ .

$2 x (x) + 2 x (- 4) = 0$

Factor $2 x$ out of $2 x (x) + 2 x (- 4)$ .

$2 x (x - 4) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x - 4 = 0$

Step 4

Set $x$ equal to $0$ .

$x = 0$

Step 5

Set $x - 4$ equal to $0$ and solve for $x$ .

Set $x - 4$ equal to $0$ .

$x - 4 = 0$

Add $4$ to both sides of the equation.

$x = 4$

Step 6

The final solution is all the values that make $2 x (x - 4) = 0$ true.

$x = 0, 4$